State Engineering Entrances - South India (KCET, COMEDK, EAMCET & KEAM) previous year questions (PYQ)

2026 (30300 questions)

Q1.

[Engineering Mathematics - CET Assessment #350] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

3 / 5

(B)

1

(C)

5 / 3

(D)

15

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Q2.

[Engineering Chemistry - CET Assessment #26] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

N2 and CO (Bond Order = 3)

(B)

CO and NO (Bond Order = 2)

(C)

O2 and N2 (Bond Order = 2.5)

(D)

F2 and O2^2- (Bond Order = 2)

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2025 (72 questions)

Q1.

[Engineering Mathematics - CET Assessment #176] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

5 / 3

(B)

3 / 5

(C)

15

(D)

1

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Q2.

[Engineering Mathematics - CET Assessment #267] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

5 / 3

(B)

3 / 5

(C)

15

(D)

1

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2024 (104 questions)

Q1.

[Engineering Physics - CET Assessment #420] A body of mass m is projected from the surface of Earth (radius R, mass M) with escape velocity v_e. What is the expression for v_e?

(A)

v_e = √(GM / R) = √(gR)

(B)

v_e = 2√(GM / R)

(C)

v_e = √(2GM / R) = √(2gR)

(D)

v_e = √(GM / 2R)

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Q2.

[Engineering Mathematics - CET Assessment #186] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

3 / 5

(B)

1

(C)

5 / 3

(D)

15

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2023 (72 questions)

Q1.

[Engineering Chemistry - CET Assessment #454] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

N2 and CO (Bond Order = 3)

(B)

F2 and O2^2- (Bond Order = 2)

(C)

CO and NO (Bond Order = 2)

(D)

O2 and N2 (Bond Order = 2.5)

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Q2.

[Engineering Chemistry - CET Assessment #174] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

N2 and CO (Bond Order = 3)

(B)

CO and NO (Bond Order = 2)

(C)

O2 and N2 (Bond Order = 2.5)

(D)

F2 and O2^2- (Bond Order = 2)

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2022 (72 questions)

Q1.

[Engineering Mathematics - CET Assessment #286] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

1

(B)

5 / 3

(C)

15

(D)

3 / 5

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Q2.

[Engineering Chemistry - CET Assessment #148] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

F2 and O2^2- (Bond Order = 2)

(B)

N2 and CO (Bond Order = 3)

(C)

O2 and N2 (Bond Order = 2.5)

(D)

CO and NO (Bond Order = 2)

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2021 (72 questions)

Q1.

[Engineering Chemistry - CET Assessment #103] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

O2 and N2 (Bond Order = 2.5)

(B)

CO and NO (Bond Order = 2)

(C)

F2 and O2^2- (Bond Order = 2)

(D)

N2 and CO (Bond Order = 3)

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Q2.

[Engineering Physics - CET Assessment #302] A body of mass m is projected from the surface of Earth (radius R, mass M) with escape velocity v_e. What is the expression for v_e?

(A)

v_e = 2√(GM / R)

(B)

v_e = √(2GM / R) = √(2gR)

(C)

v_e = √(GM / 2R)

(D)

v_e = √(GM / R) = √(gR)

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2020 (72 questions)

Q1.

[Engineering Mathematics - CET Assessment #262] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

15

(B)

3 / 5

(C)

1

(D)

5 / 3

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Q2.

[Engineering Mathematics - CET Assessment #262] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

15

(B)

3 / 5

(C)

1

(D)

5 / 3

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2019 (72 questions)

Q1.

[Engineering Chemistry - CET Assessment #483] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

O2 and N2 (Bond Order = 2.5)

(B)

CO and NO (Bond Order = 2)

(C)

N2 and CO (Bond Order = 3)

(D)

F2 and O2^2- (Bond Order = 2)

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Q2.

[Engineering Chemistry - CET Assessment #483] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

O2 and N2 (Bond Order = 2.5)

(B)

CO and NO (Bond Order = 2)

(C)

N2 and CO (Bond Order = 3)

(D)

F2 and O2^2- (Bond Order = 2)

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2018 (74 questions)

Q1.

[Engineering Chemistry - CET Assessment #389] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

CO and NO (Bond Order = 2)

(B)

N2 and CO (Bond Order = 3)

(C)

F2 and O2^2- (Bond Order = 2)

(D)

O2 and N2 (Bond Order = 2.5)

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Q2.

[Engineering Mathematics - CET Assessment #293] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

3 / 5

(B)

15

(C)

1

(D)

5 / 3

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2017 (74 questions)

Q1.

[Engineering Physics - CET Assessment #121] A body of mass m is projected from the surface of Earth (radius R, mass M) with escape velocity v_e. What is the expression for v_e?

(A)

v_e = 2√(GM / R)

(B)

v_e = √(2GM / R) = √(2gR)

(C)

v_e = √(GM / 2R)

(D)

v_e = √(GM / R) = √(gR)

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Q2.

[Engineering Chemistry - CET Assessment #193] Which pair of species is isoelectronic and has identical bond order according to Molecular Orbital Theory?

(A)

N2 and CO (Bond Order = 3)

(B)

O2 and N2 (Bond Order = 2.5)

(C)

CO and NO (Bond Order = 2)

(D)

F2 and O2^2- (Bond Order = 2)

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2016 (74 questions)

Q1.

[Engineering Physics - CET Assessment #156] A body of mass m is projected from the surface of Earth (radius R, mass M) with escape velocity v_e. What is the expression for v_e?

(A)

v_e = √(GM / 2R)

(B)

v_e = √(GM / R) = √(gR)

(C)

v_e = √(2GM / R) = √(2gR)

(D)

v_e = 2√(GM / R)

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Q2.

[Engineering Physics - CET Assessment #225] A body of mass m is projected from the surface of Earth (radius R, mass M) with escape velocity v_e. What is the expression for v_e?

(A)

v_e = 2√(GM / R)

(B)

v_e = √(GM / 2R)

(C)

v_e = √(GM / R) = √(gR)

(D)

v_e = √(2GM / R) = √(2gR)

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2015 (74 questions)

Q1.

[Engineering Mathematics - CET Assessment #290] Evaluate the limit: lim (x -> 0) [sin(5x) / tan(3x)]

(A)

5 / 3

(B)

3 / 5

(C)

15

(D)

1

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Q2.

[Engineering Physics - CET Assessment #411] A body of mass m is projected from the surface of Earth (radius R, mass M) with escape velocity v_e. What is the expression for v_e?

(A)

v_e = √(2GM / R) = √(2gR)

(B)

v_e = √(GM / R) = √(gR)

(C)

v_e = 2√(GM / R)

(D)

v_e = √(GM / 2R)

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