Competitive Exam

Trigonometry question bank (Quantitative Aptitude)

Practice 650 free Competitive Exam Quantitative Aptitude - Trigonometry questions with answers and step-by-step solutions.

Q1.

If $\tan \theta = \frac{x \sin \phi}{1 - x \cos \phi}$ and $\tan \phi = \frac{y \sin \theta}{1 - y \cos \theta}$,then $\frac{x}{y} =$

(A)
$\frac{\sin \phi}{\sin \theta}$
(B)
$\frac{\sin \theta}{\sin \phi}$
(C)
$\frac{\sin \phi}{1 - \cos \theta}$
(D)
$\frac{\sin \theta}{1 - \cos \phi}$
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Q2.

If $\cot \theta + \tan \theta = m$ and $\sec \theta - \cos \theta = n,$ then which of the following is correct?

(A)
$m(mn^2)^{1/3} - n(nm^2)^{1/3} = 1$
(B)
$m(m^2n)^{1/3} - n(mn^2)^{1/3} = 1$
(C)
$n(mn^2)^{1/3} - m(nm^2)^{1/3} = 1$
(D)
$n(m^2n)^{1/3} - m(mn^2)^{1/3} = 1$
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