Let the line $x - y = 4$ intersect the circle $C: (x-4)^2 + (y+3)^2 = 9$ at the points $Q$ and $R$. If $P(\alpha, \beta)$ is a point on $C$ such that $PQ = PR$, then $(6\alpha + 8\beta)^2$ is equal to __________.
Engineer & Medical
Circle question bank (Maths)
Practice 1,597 free Engineer & Medical Maths - Circle questions with answers and step-by-step solutions.
Q1.
Verified Answer & Solution Locked
Sign in to your free student account to reveal verified answers, instant hints, and detailed explanations.
Q2.
Let $C$ be a circle having centre in the first quadrant and touching the $x$-axis at a distance of $3$ units from the origin. If the circle $C$ has an intercept of length $6\sqrt{3}$ on $y$-axis, then the length of the chord of the circle $C$ on the line $x - y = 3$ is :
Show answer & solution
Verified Answer & Solution Locked
Sign in to your free student account to reveal verified answers, instant hints, and detailed explanations.
Protected Questions
Unlock All 797 Questions in Circle
Log in or sign up free to access every question with complete solutions, create chapter practice tests, and track your performance.
Sign up free to access all 797 questions
Unlock every Circle question, generate papers, and practice at your own pace.