MHT-CET

14. Inverse Trigonometric Functions question bank (Mathematics)

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Q1.

If $a^2+b^2+c^2=r^2$,then the value of $\tan ^{-1}\left(\frac{a b}{c r}\right)+\tan ^{-1}\left(\frac{b c}{a r}\right)+\tan ^{-1}\left(\frac{c a}{b r}\right)=$

(A)

$\frac{\pi}{2}$

(B)

$\frac{\pi}{3}$

(C)

$\frac{\pi}{4}$

(D)

$\frac{\pi}{6}$

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Q2.

The number of solutions of $\tan^{-1}\left(x+\frac{2}{x}\right) - \tan^{-1}\left(\frac{4}{x}\right) - \tan^{-1}\left(x-\frac{2}{x}\right) = 0$ is:

(A)

$1$

(B)

$2$

(C)

$3$

(D)

$0$

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