Q1.
If foci of the ellipse $\frac{x^{2}}{16}+\frac{y^{2}}{b^{2}}=1\left(b^{2} \lt 16\right)$ and the hyperbola $\frac{x^{2}}{144}-\frac{y^{2}}{81}=\frac{1}{25}$ coincide, then the value of $b^{2}$ is
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