MHT-CET

Vector Algebra question bank (Mathematics)

Practice 481 free MHT-CET Mathematics - Vector Algebra questions with answers and step-by-step solutions.

Q1.

If $\bar{a}, \bar{b}, \bar{c}$ are three vectors such that $|\bar{a}|=\sqrt{31}, 4|\bar{b}|=|\bar{c}|=2$ and $2(\bar{a} \times \bar{b})=3(\bar{c} \times \bar{a})$ and if the angle between $\bar{b}$ and $\bar{c}$ is $\frac{2\pi}{3}$,then $\left|\frac{\bar{a} \times \bar{c}}{\bar{a} \cdot \bar{b}}\right|^2=$

(A)
$1$
(B)
$2$
(C)
$3$
(D)
$11$
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Q2.

If $\vec{a} = 7\hat{j} + 10\hat{k}$, $\vec{b} = -\hat{i} + 6\hat{j} + 6\hat{k}$ and $\vec{c} = -4\hat{i} + 9\hat{j} + 6\hat{k}$ are the position vectors of the vertices $A, B$ and $C$ respectively of $\triangle ABC$. Then the position vector of the point where the bisector of the angle $A$ meets side $BC$ is

(A)
$(2 - 3\sqrt{2})\hat{i} + (3 + 3\sqrt{2})\hat{j} + 6\hat{k}$
(B)
$(2 + 3\sqrt{2})\hat{i} + (3 + 3\sqrt{2})\hat{j} + 6\hat{k}$
(C)
$(2 - 3\sqrt{2})\hat{i} + (3 - 3\sqrt{2})\hat{j} + 6\hat{k}$
(D)
$(2 - 3\sqrt{2})\hat{i} + (3 + 3\sqrt{2})\hat{j} - 6\hat{k}$
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