28. Wave Optics question bank (Physics)

$V=C \cos(i_p)$

$V \cos(i_p) = C \sin(i_p)$

$C = V \cot(i_p)$

$V \sin(i_p) = C \cos(i_p)$

If the Brewster's angle for the light propagation from air to glass is $\theta$, then the Brewster's angle for the light propagating from glass to air is $(\frac{\pi}{2} - \theta)$.

The Brewster's angle for the light propagating from the glass to air is $\tan^{-1}(\frac{1}{\mu})$, where $\mu$ is the refractive index of glass.

If the Brewster's angle for light propagating from air to glass is $\theta$, then the Brewster's angle for the light propagating from glass to air is $(\pi + \theta)$.

The Brewster's angle for light propagating from glass to air is $\tan(\mu)$, where $\mu$ is the refractive index of glass.